获得指令文件类型的文件名
https://www.cnblogs.com/qiu-hua/p/7810764.html
https://blog.csdn.net/qq_40821274/article/details/97406591
https://blog.csdn.net/lsq2902101015/article/details/51305825
https://blog.csdn.net/u013555719/article/details/84502105
Python
import numpy as np
import os
path = 'F:\\wenjian'#指定文件所在路径
filetype ='.csv'#指定文件类型
def get_filename(path,filetype):
name =[]
final_name = []
for root,dirs,files in os.walk(path):
for i in files:
if filetype in i:
name.append(i.replace(filetype,''))#生成不带‘.csv’后缀的文件名组成的列表
final_name = [item +'.csv' for item in name]#生成‘.csv’后缀的文件名组成的列表
final_name.sort()
return final_name#输出由有‘.csv’后缀的文件名组成的列表